include<stdio.h>

long is_backward(long a);

int main()
{
long number,backnumber;
int i;

printf("请输入一个整数：");
scanf("%ld",&number);

backnumber = is_backward(number);

for (i = 1;i <= 7;i++)
{
    if (number == backnumber)
    {
        printf("经过%d次后该数为回数：%d",i,number);
        break;
    }
    
    number = backnumber + number;
    backnumber = is_backward(number);

}


return 0;

}

long is_backward(long a)
{

while(a/10) {
    printf("%d", a%10);
    a /=10;
}

return a;

}

请输入一个整数：68
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