帮忙看看下面的代码问题 看看最下面的输出结果对不对 简要说明理由
0
悬赏园豆：20
[已解决问题]
解决于 2011-09-29 16:22
publicclass Test1
{
private int _age=10;
public int Age
{
get { return _age; }
set { _age = value; }
}
public virtual void Output1(string name)
{
name ="Test1";
Console.Write("Test1.Output1 ：Name is "+ name);
}
public virtual void Output2(ref stringrefname)
{
refname = "Test1";
Console.Write("Test1.Output2 ：Name is " + refname);
}
}
public class Test2:Test1
{
private int _age=20;
public override void Output1(stringname)
{
name ="Test2";
Console.Write("Test2.Output1 ：Name is "+ name);
}
public new void Output2(ref stringrefname)
{
refname = "Test2";
Console.Write("Test2.Output2 ：Name is " + refname);
}
}
string name = "Name";
string refname = "RefName";
Test1 t1 = new Test2();
t1.Output1(name); //输出1？
t1.Output2(ref refname); // 输出2？
Console.Write(name); // 输出3？
Console.Write(refname); // 输出4？
Test2 t2 = new Test2();
Console.Write(t2.Age.ToString()); //输出5以及是否装箱？
t2.Output2(ref refname); //输出6
最佳答案
0
Test2类重写了Test1类的OutPut1方法，隐藏了OutPut2方法，因此t1.OutPut1(name)输出应该调用的是重写后的方法即t2中的方法，输出应为：est2.Output1 ：Name is Test2；t1.OutPut2(ref refname)输出应该是：Test1.Output2 ：Name is Test1。Console.Write(name)输出为：Name;Console.Write(refName）应为Test2。Console.Write(t2.Age.ToString())不是很清楚。t2.Output2(ref refname)输出：Test2.Output2 ：Name is test2
收获园豆：20
