C# 获取xml相同节点属性

-1

悬赏园豆：10 [已解决问题] 解决于 2009-05-08 11:34

XML样式如下：

Code
<?xml version=1.0"?>
<pdml  version="0" creator="wireshark/1.0.6">
<packet>
<proto name="address" show="192.168.0.2" />
<proto name="port" show="8080"/>
</packet>
<packet>
<proto name="address" show="192.168.0.3" />
<proto name="port" show="8080"/>
</packet>
<packet>
<proto name="address" show="192.168.0.12" />
<proto name="port" show="8000"/>
</packet>
<packet>
<proto name="address" show="192.168.0.2" />
<proto name="port" show="8080"/>
</packet>
<packet>
<proto name="address" show="192.168.0.22" />
<proto name="port" show="8880"/>
</packet>
</pdml>