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我的这个js中的方法怎样在另一个html中去调用

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[待解决问题]

我想进行解码 这个js中方法怎样去调用

 

 

/*!
* jquery.base64.js 0.1 - https://github.com/yckart/jquery.base64.js
* Makes Base64 en & -decoding simpler as it is.
*
* Based upon: https://gist.github.com/Yaffle/1284012
*
* Copyright (c) 2012 Yannick Albert (http://yckart.com)
* Licensed under the MIT license (http://www.opensource.org/licenses/mit-license.php).
* 2013/02/10
**/
;(function($) {

var b64 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/",
a256 = '',
r64 = [256],
r256 = [256],
i = 0;

var UTF8 = {

/**
* Encode multi-byte Unicode string into utf-8 multiple single-byte characters
* (BMP / basic multilingual plane only)
*
* Chars in range U+0080 - U+07FF are encoded in 2 chars, U+0800 - U+FFFF in 3 chars
*
* @param {String} strUni Unicode string to be encoded as UTF-8
* @returns {String} encoded string
*/
encode: function(strUni) {
alert("fsdfs");
// use regular expressions & String.replace callback function for better efficiency
// than procedural approaches
var strUtf = strUni.replace(/[\u0080-\u07ff]/g, // U+0080 - U+07FF => 2 bytes 110yyyyy, 10zzzzzz
function(c) {
var cc = c.charCodeAt(0);
return String.fromCharCode(0xc0 | cc >> 6, 0x80 | cc & 0x3f);
})
.replace(/[\u0800-\uffff]/g, // U+0800 - U+FFFF => 3 bytes 1110xxxx, 10yyyyyy, 10zzzzzz
function(c) {
var cc = c.charCodeAt(0);
return String.fromCharCode(0xe0 | cc >> 12, 0x80 | cc >> 6 & 0x3F, 0x80 | cc & 0x3f);
});
return strUtf;
},

/**
* Decode utf-8 encoded string back into multi-byte Unicode characters
*
* @param {String} strUtf UTF-8 string to be decoded back to Unicode
* @returns {String} decoded string
*/
decode: function(strUtf) {
// note: decode 3-byte chars first as decoded 2-byte strings could appear to be 3-byte char!
var strUni = strUtf.replace(/[\u00e0-\u00ef][\u0080-\u00bf][\u0080-\u00bf]/g, // 3-byte chars
function(c) { // (note parentheses for precence)
var cc = ((c.charCodeAt(0) & 0x0f) << 12) | ((c.charCodeAt(1) & 0x3f) << 6) | (c.charCodeAt(2) & 0x3f);
return String.fromCharCode(cc);
})
.replace(/[\u00c0-\u00df][\u0080-\u00bf]/g, // 2-byte chars
function(c) { // (note parentheses for precence)
var cc = (c.charCodeAt(0) & 0x1f) << 6 | c.charCodeAt(1) & 0x3f;
return String.fromCharCode(cc);
});
return strUni;
}
};

while(i < 256) {
var c = String.fromCharCode(i);
a256 += c;
r256[i] = i;
r64[i] = b64.indexOf(c);
++i;
}

function code(s, discard, alpha, beta, w1, w2) {
s = String(s);
var buffer = 0,
i = 0,
length = s.length,
result = '',
bitsInBuffer = 0;

while(i < length) {
var c = s.charCodeAt(i);
c = c < 256 ? alpha[c] : -1;

buffer = (buffer << w1) + c;
bitsInBuffer += w1;

while(bitsInBuffer >= w2) {
bitsInBuffer -= w2;
var tmp = buffer >> bitsInBuffer;
result += beta.charAt(tmp);
buffer ^= tmp << bitsInBuffer;
}
++i;
}
if(!discard && bitsInBuffer > 0) result += beta.charAt(buffer << (w2 - bitsInBuffer));
return result;
}

var Plugin = $.base64 = function(dir, input, encode) {
return input ? Plugin[dir](input, encode) : dir ? null : this;
};

Plugin.btoa = Plugin.encode = function(plain, utf8encode) {
plain = Plugin.raw === false || Plugin.utf8encode || utf8encode ? UTF8.encode(plain) : plain;
plain = code(plain, false, r256, b64, 8, 6);
return plain + '===='.slice((plain.length % 4) || 4);
};

Plugin.atob = Plugin.decode = function(coded, utf8decode) {
coded = String(coded).split('=');
var i = coded.length;
do {--i;
coded[i] = code(coded[i], true, r64, a256, 6, 8);
} while (i > 0);
coded = coded.join('');
return Plugin.raw === false || Plugin.utf8decode || utf8decode ? UTF8.decode(coded) : coded;
};
}(jQuery));

Eunhye丶的主页 Eunhye丶 | 菜鸟二级 | 园豆:202
提问于:2016-10-19 12:55
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所有回答(1)
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首先你需要去了解js的闭包,因为

(function(){

..........

})(.......)

这样的结构就是把里面的脚本给闭包了,如果想用里面的变量或方法的话,那么你里面就要写出全局方法了,这样问题就来了,既然都是要全局的写法,就不如直接定义一个全局方法来提供方法接口。

闲话了一番回到问题:

方法一:

var UTF8 = {前面的var字符去掉。

方法二:

(function(){

..........

})(.......)去掉最外面的(function(){})();

方法三:重写一个构造函数。

方法四:既然用了jquery,那直接用jq的插件机制(个人推荐)

 

张云山 | 园豆:642 (小虾三级) | 2016-10-19 13:48

 受教了,谢谢。

 

支持(0) 反对(0) Eunhye丶 | 园豆:202 (菜鸟二级) | 2016-12-07 15:39
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