算法设计问题，小白一个求大神带飞
0
最佳答案
0
正好之前给人做过这个题目.
重点是:一个每月天数数组.一个输入年份月份获取当月天数方法.然后就是循环加了.
int[] day4m=[31,28,31,30,31,30,31,31,30,31,30,31]
function int day4ym(int year,int m){if(m==2){判断闰年返回day4m[m-1]+1}else{return day4m[m-1];}}
然后就是循环月份的次数.把之前所有月份的天数加起来.再加上日数.就是结果.
收获园豆：50
大神，能不能给个完整代码，我好琢磨琢磨。
@遥路漫漫:
function day4year( y, m, d ) { var day4m = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]; if ( y < 0 || m < 0 || d < 0 ) { return -1; } if ( m > 12 ) { return -1; } if ( d > day4m[m] ) { return -1; } var rt = d; for ( var i = 0; i < m; i++ ) { rt += day4m[i]; } if ( isLeapYear( y ) && m > 2 ) { rt += 1; } return rt; } function isLeapYear( y ) { return ( ( ( y % 4 ) == 0 ) && ( y % 100 ) != 0 ) || ( y % 400 == 0 ); }
说实话.你问题大...
@吴瑞祥: 大神能在帮个忙吗？
这里有java的代码 ， 您能不能翻译成c代码？
package mec.lanqiao; import java.util.*; public class Main { static char[] upper = { '零', '壹', '贰', '叁', '肆', '伍', '陆', '柒', '捌', '玖' }; // 大写数字 // 获取一个四位数的大写字符串，零的数目可以为多个 static String addZero(String t) { StringBuilder sb = new StringBuilder(); int n1 = Integer.parseInt("" + t.charAt(0)); int n2 = Integer.parseInt("" + t.charAt(1)); int n3 = Integer.parseInt("" + t.charAt(2)); int n4 = Integer.parseInt("" + t.charAt(3)); if (n1 == 0) { sb.append("零"); } else { sb.append(upper[n1] + "仟"); } if (n2 == 0) { sb.append("零"); } else { sb.append(upper[n2] + "佰"); } if (n3 == 0) { sb.append("零"); } else { sb.append(upper[n3] + "拾"); } if (n4 != 0) { sb.append(upper[n4]); } return sb.toString(); } static void f(String num) { int len = num.length(); if (len < 5) { for (int i = 0; i < 4 - len; i++) { num = "0" + num; } String s = addZero(num); // 去尾部的零 while (s.endsWith("零")) { s = s.substring(0, s.length() - 1); } // 去首部的零 while (s.startsWith("零")) { s = s.substring(1); } // 消除重复的零 s = s.replaceAll("零零零", "零"); s = s.replaceAll("零零", "零"); System.out.println(s); } else if (len < 9) { String s, s1, s2; s1 = num.substring(0, num.length() - 4); int i = 4 - s1.length(); while (i-- > 0) { s1 = "0" + s1; } s1 = addZero(s1) + "万"; s2 = num.substring(num.length() - 4); s2 = addZero(s2); s = s1 + s2; while (s.endsWith("零")) { s = s.substring(0, s.length() - 1); } while (s.startsWith("零")) { s = s.substring(1); } s = s.replaceAll("零零零", "零"); s = s.replaceAll("零零", "零"); System.out.println(s); } else { String s, s1, s2, s3; s1 = num.substring(0, num.length() - 8); int i = 4 - s1.length(); while (i-- > 0) { s1 = "0" + s1; } s2 = num.substring(num.length() - 8, num.length() - 4); s3 = num.substring(num.length() - 4); s1 = addZero(s1) + "亿"; s2 = addZero(s2) + "万"; s3 = addZero(s3); s = s1 + s2 + s3; while (s.endsWith("零")) { s = s.substring(0, s.length() - 1); } while (s.startsWith("零")) { s = s.substring(1); } s = s.replaceAll("零零零", "零"); s = s.replaceAll("零零", "零"); System.out.println(s); } } public static void main(String[] args) { Scanner scan = new Scanner(System.in); String num = scan.next(); scan.close(); f(num); }}
其他回答(1)
0
#include <conio.h>
#include<stdio.h>
void main()
{
int days[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int i,j,k,y,m,d,b,n,sum;
int N=0;
int year[100];
int month[100];
int day[100];
scanf("%d",&N);
printf("日期输入格式：2010-6-9 \n");
for(i=0;i<N;i++)
scanf("%d-%d-%d",&year[i],&month[i],&day[i]);
for(j=0;j<N;j++)
{
sum=0;
for(i=1;i<month[j];i++)
sum=sum+days[i];
sum=sum+day[j];
if((year[j]%4==0||(year[j]%400==0&&year[j]%100!=0)) &&month[j]>2)
sum=sum+1;
printf("%d\n",sum);
}
getch();
}
