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Unity在WebGL中无法反序列化xml到dll中的Model层

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悬赏园豆:180 [待解决问题]

任务是在WebGL中从StreamingAssets中读取xml文件并反序列化。现在结果是:如果Model不在dll中定义,则WebGL中能够反序列化,但如果在dll中定义,则在WebGL中无法反序列化,研究了好几天了,还是无法解决,网上也没有找到类似的,还望大家帮忙QAQ。

下面是我目前的做法:

在Unity中反序列化:

 1 using System.Collections;
 2 using UnityEngine;
 3 using UnityEngine.Networking;
 4 using WillConfiguration;
 5 using System.IO;
 6 using System.Xml.Serialization;
 7 
 8 public class ReadWillXML : MonoBehaviour
 9 {
10     public string xmlName;
11     public WillXMLConfiguration willXMLConfiguration;
12 
13     // Start is called before the first frame update
14     IEnumerator Start()
15     {
16         UnityWebRequest uwr = UnityWebRequest.Get(Path.Combine(Application.streamingAssetsPath, xmlName));
17         yield return uwr.SendWebRequest();
18 
19         StringReader sr = new StringReader(uwr.downloadHandler.text);
20         sr.ReadLine();
21         XmlSerializer serializer = new XmlSerializer(typeof(WillXMLConfiguration));
22         willXMLConfiguration = (WillXMLConfiguration)serializer.Deserialize(sr);
23 
24         sr.Close();
25         Debug.Log("### Number = " + willXMLConfiguration.Number);
26         Debug.Log("### Frontwards = " + willXMLConfiguration.Frontwards);
27         Debug.Log("### Position X = " + willXMLConfiguration.Position.X + " Y = " + willXMLConfiguration.Position.Y);
28         Debug.Log("The End!");
29     }
30 }

Model层的定义(Build成dll)

 1 using System.Xml.Serialization;
 2 using System.Runtime.Serialization;
 3 
 4 namespace WillConfiguration
 5 {
 6     
 7     [XmlRoot(ElementName = "WillConfiguration"), DataContract(Name = "WillConfiguration")]
 8     public class WillXMLConfiguration
 9     {
10         [XmlAttribute(AttributeName = "Number"), DataMember(Name = "Number")]
11         public string Number { get; set; }
12         [XmlAttribute(AttributeName = "Frontwards"), DataMember(Name = "Frontwards")]
13         public bool Frontwards { get; set; }
14         [XmlElement(ElementName = "Position"), DataMember(Name = "Position")]
15         public WillXMLPosition Position { get; set; }
16         public WillXMLConfiguration() { }
17     }
18 }
复制代码
 1 using System.Xml.Serialization;
 2 using System.Runtime.Serialization;
 3 
 4 namespace WillConfiguration
 5 {
 6     [XmlRoot(ElementName = "Position"), DataContract(Name = "Position")]
 7     public class WillXMLPosition
 8     {
 9         [XmlAttribute(AttributeName = "X"), DataMember(Name = "X")]
10         public float X { get; set; }
11         [XmlAttribute(AttributeName = "Y"), DataMember(Name = "Y")]
12         public float Y { get; set; }
13         [XmlAttribute(AttributeName = "Z"), DataMember(Name = "Z")]
14         public float Z { get; set; }
15     }
16 }
复制代码

xml文件(放在StreamingAssets中)

1 <?xml version="1.0" encoding="utf-8"?>
2 <WillConfiguration Number="6" Frontwards="true">
3     <Position X="1" Y="2" Z="3" />
4 </WillConfiguration>

------------------------

按照上面的代码,能在unity编辑器中运行,但build成WebGL中就报错,显示

然而在把WillXMLPosition和WillXMLConfiguration两个类加上[Serializable]后,虽然能运行,但得到的都是空值,可以确定的是确实是以字符串的形式读取了xml文件。

落星无尘_Will的主页 落星无尘_Will | 初学一级 | 园豆:17
提问于:2020-01-20 12:10
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所有回答(2)
0

看看我的博文:https://www.cnblogs.com/lzhdim/p/8227581.html

另,要考虑对象是否能够序列化。。。

lzhdim | 园豆:659 (小虾三级) | 2020-01-24 18:50
0

最后还是没有解决办法,只能傻瓜式的一一对应了。

落星无尘_Will | 园豆:17 (初学一级) | 2020-02-15 20:19
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