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关于Form的show()方法的若干问题

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[待解决问题]

public partial class Form2 : Form
    {
        public Form2()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {

            try
            {
                string a = textBox1.Text;

                int result;

                bool bl = int.TryParse(textBox2.Text, out  result);

                if (!bl)
                {
                    throw new YC();
                }
                else
                {
                    int b = int.Parse(textBox2.Text);
                    bool bl1 = ceshi(a, b);

                    if (bl1)
                    {
                       // MessageBox.Show("CHENGONG");
                        this.Close();
                       Form3 form3=new Form3();
                       form3.Show();

                    }
                    else
                    {
                        MessageBox.Show("SH");
                    }

                }
            }

            catch (YC yc)
            {
                MessageBox.Show(yc.ToString());
            }
            //string a = textBox1.Text;
            //int b= int.Parse(textBox2.Text);
            //bool bl = ceshi(a, b);
            //if (bl)
            //{
            //    MessageBox.Show("CHENGGONG");

            //}
            //else
            //{

            //    MessageBox.Show("SHIBAI");

            //}
            finally
            {

            }
     
        }

 

 

 

 

 

        public bool ceshi(string a, int b)
        {
            string connectionstring = "server=localhost;database=ceshi;integrated security=SSPI";
            SqlConnection con = new SqlConnection(connectionstring);
            con.Open();
            //string commandtext = "select * from Table_1 where name='" + a + "'and passward=" + b;
            //string @name;
            //string @passward;
            string commandtext = "select * from Table_1 where name=@name and passward = @passward";

            SqlCommand cmd = new SqlCommand(commandtext, con);
            //cmd.Parameters.Add("@name", SqlDbType.VarChar);
            //cmd.Parameters["@name"].Value = "a";
            cmd.Parameters.AddWithValue("@name", a);
            cmd.Parameters.Add("@passward", SqlDbType.Int);
            cmd.Parameters["@passward"].Value = b;

            SqlDataReader reader = cmd.ExecuteReader();
            if (reader.Read())
            {
                return true;
            }
            else
            {
                return false;
            }
            con.Close();

        }

     
    }

    class YC : ApplicationException
    {
        private string Message;
        public YC()
        {

            this.Message = "输入有误,请重新输入";
        }

        public override string ToString()
        {
            return Message;
        }

    }在设置断点调试过程中弹出了Form3窗体,后运行到方法dispose(),但是无断点时没有弹出Form3, 请高手解答一下。

870087629的主页 870087629 | 初学一级 | 园豆:170
提问于:2010-09-25 17:45
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所有回答(1)
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可能这里有问题:

  this.Close();
      Form3 form3=new Form3();  form3.Show();

因为bool bl1 = ceshi(a, b);  中的bl1是this的局部变量,this.close()表示释放this对象的资源。

出现调试会弹出,我个人没法理解,可能是因为调试,内存资源不会立即释放吧。

小闵 | 园豆:502 (小虾三级) | 2010-09-25 21:27
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