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JS获取农历日期的原理是什么,有人能解释下吗?

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[已解决问题] 解决于 2012-03-19 08:03

这篇文章讲的是用JS获取农历日期,主要代码如下:

    var CalendarData = new Array(100);
var madd = new Array(12);
var tgString = "甲乙丙丁戊己庚辛壬癸";
var dzString = "子丑寅卯辰巳午未申酉戌亥";
var numString = "一二三四五六七八九十";
var monString = "正二三四五六七八九十冬腊";
var weekString = "日一二三四五六";
var sx = "鼠牛虎兔龙蛇马羊猴鸡狗猪";
var cYear, cMonth, cDay, TheDate;
CalendarData = new Array(0xA4B, 0x5164B, 0x6A5, 0x6D4, 0x415B5, 0x2B6, 0x957, 0x2092F, 0x497, 0x60C96, 0xD4A, 0xEA5, 0x50DA9, 0x5AD, 0x2B6, 0x3126E, 0x92E, 0x7192D, 0xC95, 0xD4A, 0x61B4A, 0xB55, 0x56A, 0x4155B, 0x25D, 0x92D, 0x2192B, 0xA95, 0x71695, 0x6CA, 0xB55, 0x50AB5, 0x4DA, 0xA5B, 0x30A57, 0x52B, 0x8152A, 0xE95, 0x6AA, 0x615AA, 0xAB5, 0x4B6, 0x414AE, 0xA57, 0x526, 0x31D26, 0xD95, 0x70B55, 0x56A, 0x96D, 0x5095D, 0x4AD, 0xA4D, 0x41A4D, 0xD25, 0x81AA5, 0xB54, 0xB6A, 0x612DA, 0x95B, 0x49B, 0x41497, 0xA4B, 0xA164B, 0x6A5, 0x6D4, 0x615B4, 0xAB6, 0x957, 0x5092F, 0x497, 0x64B, 0x30D4A, 0xEA5, 0x80D65, 0x5AC, 0xAB6, 0x5126D, 0x92E, 0xC96, 0x41A95, 0xD4A, 0xDA5, 0x20B55, 0x56A, 0x7155B, 0x25D, 0x92D, 0x5192B, 0xA95, 0xB4A, 0x416AA, 0xAD5, 0x90AB5, 0x4BA, 0xA5B, 0x60A57, 0x52B, 0xA93, 0x40E95);
madd[0] = 0;
madd[1] = 31;
madd[2] = 59;
madd[3] = 90;
madd[4] = 120;
madd[5] = 151;
madd[6] = 181;
madd[7] = 212;
madd[8] = 243;
madd[9] = 273;
madd[10] = 304;
madd[11] = 334;

function GetBit(m, n) {
return (m >> n) & 1;
}
function e2c() {
TheDate = (arguments.length != 3) ? new Date() : new Date(arguments[0], arguments[1], arguments[2]);
var total, m, n, k;
var isEnd = false;
var tmp = TheDate.getYear();
if (tmp < 1900) {
tmp += 1900;
}
total = (tmp - 1921) * 365 + Math.floor((tmp - 1921) / 4) + madd[TheDate.getMonth()] + TheDate.getDate() - 38;

if (TheDate.getYear() % 4 == 0 && TheDate.getMonth() > 1) {
total++;
}
for (m = 0; ; m++) {
k = (CalendarData[m] < 0xfff) ? 11 : 12;
for (n = k; n >= 0; n--) {
if (total <= 29 + GetBit(CalendarData[m], n)) {
isEnd = true; break;
}
total = total - 29 - GetBit(CalendarData[m], n);
}
if (isEnd) break;
}
cYear = 1921 + m;
cMonth = k - n + 1;
cDay = total;
if (k == 12) {
if (cMonth == Math.floor(CalendarData[m] / 0x10000) + 1) {
cMonth = 1 - cMonth;
}
if (cMonth > Math.floor(CalendarData[m] / 0x10000) + 1) {
cMonth--;
}
}
}

function GetcDateString() {
var tmp = "";
tmp += tgString.charAt((cYear - 4) % 10);
tmp += dzString.charAt((cYear - 4) % 12);
tmp += "(";
tmp += sx.charAt((cYear - 4) % 12);
tmp += ")年 ";
if (cMonth < 1) {
tmp += "(闰)";
tmp += monString.charAt(-cMonth - 1);
} else {
tmp += monString.charAt(cMonth - 1);
}
tmp += "月";
tmp += (cDay < 11) ? "初" : ((cDay < 20) ? "十" : ((cDay < 30) ? "廿" : "三十"));
if (cDay % 10 != 0 || cDay == 10) {
tmp += numString.charAt((cDay - 1) % 10);
}
return tmp;
}

function GetLunarDay(solarYear, solarMonth, solarDay) {
//solarYear = solarYear<1900?(1900+solarYear):solarYear;
if (solarYear < 1921 || solarYear > 2020) {
return "";
} else {
solarMonth = (parseInt(solarMonth) > 0) ? (solarMonth - 1) : 11;
e2c(solarYear, solarMonth, solarDay);
return GetcDateString();
}
}
//调用
var D = new Date();
var yy = D.getFullYear();
var mm = D.getMonth() + 1;
var dd = D.getDate();
var ww = D.getDay();
var ss = parseInt(D.getTime() / 1000);
if (yy < 100) yy = "19" + yy;
function GetCNDate() {
return GetLunarDay(yy, mm, dd);
}
$(document).ready(function () {
var d = GetCNDate();
alert(d);
});

原理是什么呢,有人能解释下吗?

观海云不远的主页 观海云不远 | 初学一级 | 园豆:89
提问于:2012-03-14 09:29
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最佳答案
0
CalendarData是一个对照表,这种都是通过查这个表来确定的
丁学 | 专家六级 |园豆:18730 | 2012-03-14 13:02
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