首页 新闻 搜索 专区 学院

线程互斥与阻塞

0
悬赏园豆:10 [已解决问题] 解决于 2012-06-14 08:23

多个线程,期望其中某一个线程因为某一种原因发出线程阻塞操作,使得别的线程在当前执行循环或下一个执行循环时进入阻塞状态,直到这个发起线程把问题处理完成后发出解除阻塞为止。

以下代码在前期没什么问题,经过几次循环后就不行了。

问题补充:
using System;
using System.Diagnostics;
using System.Threading;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            Thread[] threads = new Thread[2];
            for (int i = 0; i < threads.Length; i++)
            {
                threads[i] = new Thread(new ParameterizedThreadStart(Run));
                threads[i].Start(i);
            }
        }

        private static string uniqueID = "unique name";
        private static void Run(object state)
        {
            while (true)
            {
                bool createdNew;
                using (System.Threading.Mutex mutex = new System.Threading.Mutex(true, uniqueID, out createdNew))
                {
                    if (!createdNew)
                    {
                        //如果互斥对象被别的线程构建,等待互斥对象被释放
                        Console.WriteLine("Thread {0} Entry Wating...", state);
                        Debug.WriteLine("Thread {0} Entry Wating...", state);
                        mutex.WaitOne();
                        Console.WriteLine("Thread {0} Exit Wating...", state);
                        Debug.WriteLine("Thread {0} Exit Wating...", state);
                    }
                }
                int working = new Random().Next(1000, 3000);
                Console.WriteLine("Thread {0} Do Something for {1}...", state, working);
                Debug.WriteLine("Thread {0} Do Something for {1}...", state, working);
                Thread.Sleep(working);
                Console.WriteLine("Thread {0} Do Something ok for {1}...", state, working);
                Debug.WriteLine("Thread {0} Do Something ok for {1}...", state, working);

                bool critical = new Random().Next(1000, 3000) % 10 == 0;
                if (critical)
                {
                    Console.WriteLine("Thread {0} Entry critical...", state);
                    while (true)
                    {
                        using (System.Threading.Mutex mutex = new System.Threading.Mutex(true, uniqueID, out createdNew))
                        {
                            if (!createdNew)
                            {
                                //如果互斥对象被别的线程构建,等待互斥对象被释放
                                Console.WriteLine("Thread {0} Entry Wating for critical...", state);
                                Debug.WriteLine("Thread {0} Entry Wating for critical...", state);
                                mutex.WaitOne();
                                Console.WriteLine("Thread {0} Exit Wating for critical...", state);
                                Debug.WriteLine("Thread {0} Exit Wating for critical...", state);
                            }
                            else
                            {
                                working = new Random().Next(1000, 3000);
                                Console.WriteLine("Thread {0} Do critical Something for {1}...", state, working);
                                Debug.WriteLine("Thread {0} Do critical Something for {1}...", state, working);
                                Thread.Sleep(working);
                                Console.WriteLine("Thread {0} Do critical Something ok for {1}...", state, working);
                                Debug.WriteLine("Thread {0} Do critical Something ok for {1}...", state, working);
                                mutex.ReleaseMutex();
                                break;
                            }
                        }
                    }
                }
            }
        }
    }



}
无之无的主页 无之无 | 大侠五级 | 园豆:5085
提问于:2012-06-06 10:55
< >
分享
最佳答案
0

这个问题描述得不够详细

收获园豆:10
dudu | 高人七级 |园豆:38804 | 2012-06-06 23:00

很清楚了吧?就是多个线程并行,每个线程都有可能遇到一些特殊原因,当这样的特殊原因(可能是临界资源,也可能是灾难性故障)发生的时候,别的线程就必须进入暂停状态(由故障产生或发现线程发起暂停消息),然后等待发起线程把问题处理完成后发出解锁信息,从而使得别的线程继续运行。

我把代码补充上来,不知道怎么没代码了。

无之无 | 园豆:5085 (大侠五级) | 2012-06-07 08:09

@笨笨蜗牛: 有没有考虑过使用Task?

dudu | 园豆:38804 (高人七级) | 2012-06-07 15:45

@笨笨蜗牛: 首页有一篇不错的多线程方面的文章 —— C# 温故而知新: 线程篇(一)

dudu | 园豆:38804 (高人七级) | 2012-06-12 07:57
清除回答草稿
   您需要登录以后才能回答,未注册用户请先注册