关于在DX中顶点法线的算法
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悬赏园豆：5
[待解决问题]
一直弄不明白D3D中顶点法线是怎么求的？？求大侠指点
1 Vertex* v; 2 Pyramid->Lock(0, 0, (void**)&v, 0); 3 4 // front face 5 v[0] = Vertex(-1.0f, 0.0f, -1.0f, 0.0f, 0.707f, -0.707f); 6 v[1] = Vertex( 0.0f, 1.0f, 0.0f, 0.0f, 0.707f, -0.707f); 7 v[2] = Vertex( 1.0f, 0.0f, -1.0f, 0.0f, 0.707f, -0.707f); 8 9 // left face 10 v[3] = Vertex(-1.0f, 0.0f, 1.0f, -0.707f, 0.707f, 0.0f); 11 v[4] = Vertex( 0.0f, 1.0f, 0.0f, -0.707f, 0.707f, 0.0f); 12 v[5] = Vertex(-1.0f, 0.0f, -1.0f, -0.707f, 0.707f, 0.0f); 13 14 // right face 15 v[6] = Vertex( 1.0f, 0.0f, -1.0f, 0.707f, 0.707f, 0.0f); 16 v[7] = Vertex( 0.0f, 1.0f, 0.0f, 0.707f, 0.707f, 0.0f); 17 v[8] = Vertex( 1.0f, 0.0f, 1.0f, 0.707f, 0.707f, 0.0f); 18 19 // back face 20 v[9] = Vertex( 1.0f, 0.0f, 1.0f, 0.0f, 0.707f, 0.707f); 21 v[10] = Vertex( 0.0f, 1.0f, 0.0f, 0.0f, 0.707f, 0.707f); 22 v[11] = Vertex(-1.0f, 0.0f, 1.0f, 0.0f, 0.707f, 0.707f); 23 24 Pyramid->Unlock();
所有回答(1)
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已经弄明白了
