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android ZXing扫描二维码后将数据发送到数据库

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悬赏园豆:40 [已关闭问题] 关闭于 2012-12-30 10:05

zxing的源程序中,将CaptureActivity.java

TextView contentsTextView = (TextView) findViewById(R.id.contents_text_view);
        CharSequence displayContents = resultHandler.getDisplayContents();
        contentsTextView.setText(displayContents);
        
        

这一段下面插入一下代码,作为客户端:

new Register().execute(displayContents);

private class Register extends AsyncTask<CharSequence, Object, Object> {
        String addr = "192.168.1.108";
        int port = 4444;
        private DatagramSocket ds;

        @Override
        protected Object doInBackground(CharSequence... arg0) {
            // TODO Auto-generated method stub
            byte[] data = arg0[0].toString().getBytes();
            DatagramPacket dp = null;
            try {
                try {
                    ds = new DatagramSocket(port);
                } catch (SocketException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
                InetAddress ip = InetAddress.getByName(addr);

                dp = new DatagramPacket(data, data.length, ip, port);
                dp.setAddress(ip);
                dp.setData(data);
                dp.setLength(data.length);
                System.out.println(ip.toString());
            } catch (UnknownHostException e1) {
                // TODO Auto-generated catch block
                System.out.println("new packet failed");
            }
            try {
                ds.send(dp);
            } catch (IOException e) {
                // TODO Auto-generated catch block
                System.out.println("send failed");
            }

            return null;
        }
    }

这里面

byte[] data = arg0[0].toString().getBytes();意思是获取二维码扫描的数据是吗?
写了这个之后,server端应该怎么写呢?下面的这一段变异没有问题,但是运行的时候发现与客户端没有连上,是数据没有获取到吗?
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetAddress;
import java.net.SocketAddress;
import java.nio.ByteBuffer;

public class Server {

  public static void main(String[] args) {
    try {
      //确定接受方的IP和端口号,IP地址为本地机器地址
      InetAddress ip = InetAddress.getLocalHost();
      int port = 8888;
      
      //创建接收方的套接字,并制定端口号和IP地址
      DatagramSocket getSocket = new DatagramSocket(port,ip);
      
      //确定数据报接受的数据的数组大小
      byte[] data = new byte[1024];
     // byte[] data = args[0].toString().getBytes();
      //创建接受类型的数据报,数据将存储在buf中
      DatagramPacket getPacket = new DatagramPacket(data,data.length);
      
      //通过套接字接收数据
      getSocket.receive(getPacket);
      //ByteBuffer bbuf = ByteBuffer.wrap(data, 0, 4);  
      
      
      //解析发送方传递的消息,并打印
      String getMes = new String(data,0,getPacket.getLength());
      System.out.println("对方发送的消息:"+getMes);
      
      //通过数据报得到发送方的IP和端口号,并打印
      InetAddress sendIP = getPacket.getAddress();
      int sendPort = getPacket.getPort();
      System.out.println("对方的IP地址是:"+sendIP.getHostAddress());
      System.out.println("对方的端口号是:"+sendPort);
      
      //通过数据报得到发送方的套接字地址
      SocketAddress sendAddress = getPacket.getSocketAddress();
      
      //确定要反馈发送方的消息内容,并转换为字节数组
      String feedback = "接收方说:我收到了!";
      byte[] backBuf = feedback.getBytes();
      
      //创建发送类型的数据报
      DatagramPacket sendPacket = new DatagramPacket(backBuf,backBuf.length,sendAddress);
      
      //通过套接字发送数据
      getSocket.send(sendPacket);
      
      //关闭套接字
      getSocket.close();
    } catch (Exception e) {
      e.printStackTrace();
    }
  }

}

恳请各位帮忙,急!!



响^_^的主页 响^_^ | 初学一级 | 园豆:110
提问于:2012-11-07 21:47
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