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求这道题该怎么解?求各位大神给个详细思路

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悬赏园豆:5 [待解决问题]
矩阵是指纵横排列的数据表格,最早来自于方程组的系数及常数所构成的方阵,如:

        a11 a12... a1n    
        
        a21 a22... a2n
            ... ... ...

        am1 am2... amn 

矩阵乘积规则示例如下:

两个矩阵a和b可以相乘的条件是a矩阵的列数和b矩阵的行数相同,例如:

假设矩阵a为“3行2列”:

a11 a12 a13

a21 a22 a23

矩阵b为“2行3列”:

b11 b12

b21 b22

b31 b32

a和b可以相乘,乘积矩阵为:

a11*b11+a12*b21+a13*b31    a11*b12+a12*b22+a13*b3
a21*b11+a22*b21+a23*b31    a21*b12+a22*b22+a23*b32

Matrix类的定义如下:
public class Matrix {
private double[][] data;
private int rows;
private int cols;
public Matrix(int rows, int cols) {
     if (rows <= 0 || cols <= 0)
         throw new IllegalArgumentException(");
     this.rows = rows;
     this.cols = cols;
     data = new double[rows][cols];
}
public Matrix(int rows, int cols, String line) {
     if (rows <= 0 || cols <= 0 || line == null)
         throw new IllegalArgumentException("");
     String[] dataStr = line.split(",");
     if (  空白处1  ) {
         throw new IllegalArgumentException("");
     }
     this.rows = rows;
     this.cols = cols;
     data = new double[rows][cols];
     for (int i = 0; i < dataStr.length; i++) {
                   空白处2          
     }
}
    public Matrix mul(Matrix ma) {
     if (          空白处3          ) {
         throw new IllegalArgumentException("");
     }
     Matrix mc = new Matrix(rows, ma.cols);
     for (int i = 0; i < mc.getRows(); i++) {
         for (int j = 0; j < mc.getCols(); j++) {
             for (          空白处4          ) {
                           空白处5         
             }
         }
     }
     return mc;
}
public int getRows() {
     return rows;
}
public int getCols() {
     return cols;
}
public String toString() {
     StringBuilder sb = new StringBuilder();
     for (int i = 0; i < rows; i++) {
         for (int j = 0; j < cols - 1; j++) {
             sb.append(data[i][j]).append(",");
         }
         sb.append(data[i][cols - 1]).append("\n");
     }
     return sb.toString();
   }
}
下列选项中,能填入空白处1的代码是(    )
  A. dataStr.length != (rows-1) * (cols-1)
 B. dataStr.length != (rows-1) * cols
 C. dataStr.length != rows * cols
 D. dataStr.length != rows * (cols-1)

 37. 下列选项中,能填入空白处2的代码是(    )
  A. data[i % cols][i / cols] = Double.parseDouble(dataStr[i]);
 B. data[i/cols][i % cols] = Double.parseDouble(dataStr[i]);
 C. data[i/ rows][i % rows] = Double.parseDouble(dataStr[i]);
 D. data[i % rows][i /rows] = Double.parseDouble(dataStr[i]);

 38. 下列选项中,能填入空白处3的代码是(    )
  A. cols != ma.cols
 B. rows != ma.cols
 C. rows != ma.rows
 D. cols != ma.rows

 39. 下列选项中,能填入空白处4的代码是(    )
  A. int k = 0; k < cols; k++
 B. int k = 0; k <ma.cols; k++
 C. int k = 0; k <rows; k++
 D. int k = 0; k <rows * ma.cols; k++

 40. 下列选项中,能填入空白处5的代码是(    )
  A. mc.data[i][j] += data[k][j] * ma.data[i][k];
 B. mc.data[i][j] += data[k][i] * ma.data[j][k];
 C. mc.data[i][j] += data[j][k] * ma.data[k][i];
 D. mc.data[i][j] += data[i][k] * ma.data[k][j];
neal2004的主页 neal2004 | 菜鸟二级 | 园豆:206
提问于:2013-05-16 23:58
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所有回答(2)
0

这个意思,关注一下

@@@一统@@@ | 园豆:1551 (小虾三级) | 2013-05-17 12:40
0

我晕 这不找人代做嘛

二十三号同学 | 园豆:974 (小虾三级) | 2013-05-22 11:16
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