winfrom中，listview读取显示XML，新手！求代码！谢谢啊！！显示时间，和报警信息
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悬赏园豆：50
[已关闭问题]
关闭于 2013-08-28 10:02
<?xml version="1.0" encoding="utf-8" ?>
<warnlist count="2" lastnumber="2">
<warn number="1" nvsid="2001181" type="31" datetime="2013-08-19 17:32:01">2001181-无视频信号</warn>
<warn number="2" nvsid="2001182" type="31" datetime="2013-08-19 17:32:13">2001182-无视频信号</warn>
</warnlist>
所有回答(3)
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http://stackoverflow.com/questions/3812277/how-to-display-data-from-xml-file-to-listview-using-linq-to-xml
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XML反序列化为对象，也是一种思路~
当然LinqToXML也挺好的~
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XmlDocument xml = new XmlDocument();
var xmlStr = File.ReadAllText("nvs_warn.xml");
xml.LoadXml(xmlStr);
var node = xml.SelectSingleNode("warnlist");
var names = new List<string>();
foreach (XmlNode studentNode in node.ChildNodes)
{
listView1.Items.Add(studentNode.InnerText);
}
