我写了一个手动输入后收集专辑信息的程序，写的很繁杂......是定义了一个可以将实参整理入字典的函数，再将字典放入列表
 album_list = []
def album(name, singer, quantities_of_songs):
    """record the info of a album"""                                         
    info = {'name': a, 'singer': b, 'numbers ': c}

    return info
while True:
    a = input("input the name.\ninput 'q' to exit\n")
    if a == 'q' :
        b = c = 'q'
        break
    b = input("input the singer's name\n")
    if b == 'q':
        c = 'q'
        break
    c = input("input the number of songs\n")
    if c == 'q':
        break
    recorded_album = album(a, b, c)
    album_list.append(recorded_album)
    question = input("do you have any other album?(yes/no)")
    if question == 'no':
        break
if a and b and c != 'q':
    print("\n"*3)
    print(album_list)
    
然而最后print出来的list是多个字典紧挨着排列在一起的，能否在每个元素之间插入空行使结构整洁一点