键重复的情况下，如何取出某个对象？或者如何取出相同键的一组？
0
悬赏园豆：5
[已解决问题]
解决于 2019-09-18 17:45
var my_sys_roletujing_json={"1":"1102","1":"1103","1":"1104","1":"1105","1":"1107","1":"1108","1":"1111","1":"1112","1":"1113","1":"1114","1":"1115","1":"1116","1":"1119","1":"1120","1":"1123","1":"1125","1":"1126","1":"1127","1":"1128","1":"1129","1":"1130","1":"1131","1":"1135","1":"1136","1":"1138","1":"1139","1":"1154","1":"1155","1":"1156","1":"1159","1":"1160","1":"1161","1":"1162","1":"1163","1":"1164","1":"1165","1":"1166","1":"1172","1":"1173","1":"1175","1":"1176","1":"1177","1":"1180","3":"150","3":"151","3":"153","3":"154","3":"157","3":"158","3":"159","3":"160"};
最佳答案
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这个是要js处理么?
不同语言不一样的。
如果按照你的这个js写：{1: "1180", 3: "160"}，结果只是这个。
整理数据：
var data_list=[];
var my_sys_roletujing_json =
'{"1":"1102","1":"1103","1":"1104","1":"1105","1":"1107","1":"1108","1":"1111","1":"1112","1":"1113","1":"1114","1":"1115","1":"1116","1":"1119","1":"1120","1":"1123","1":"1125","1":"1126","1":"1127","1":"1128","1":"1129","1":"1130","1":"1131","1":"1135","1":"1136","1":"1138","1":"1139","1":"1154","1":"1155","1":"1156","1":"1159","1":"1160","1":"1161","1":"1162","1":"1163","1":"1164","1":"1165","1":"1166","1":"1172","1":"1173","1":"1175","1":"1176","1":"1177","1":"1180","3":"150","3":"151","3":"153","3":"154","3":"157","3":"158","3":"159","3":"160"}';
var myregexp = /"([0-9]*)":"([0-9]*)"/g;
var match = myregexp.exec(my_sys_roletujing_json);
var i=0
while (match != null) {
data_list.push({key:match[1],value:match[2]})
match = myregexp.exec(my_sys_roletujing_json);
}
console.log(data_list)
1.如何取出某个对象
遍历列表，判断value=x
2.如何取出相同键的一组
遍历列表，判断key=x
收获园豆：5
非常感谢
其他回答(2)
0
自己解析字符串吧，如果没有合适的类库
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<script>
var my_sys_roletujing_json='{"1":"1102","1":"1103","1":"1104","1":"1105","1":"1107","1":"1108","1":"1111","1":"1112","1":"1113","1":"1114","1":"1115","1":"1116","1":"1119","1":"1120","1":"1123","1":"1125","1":"1126","1":"1127","1":"1128","1":"1129","1":"1130","1":"1131","1":"1135","1":"1136","1":"1138","1":"1139","1":"1154","1":"1155","1":"1156","1":"1159","1":"1160","1":"1161","1":"1162","1":"1163","1":"1164","1":"1165","1":"1166","1":"1172","1":"1173","1":"1175","1":"1176","1":"1177","1":"1180","3":"150","3":"151","3":"153","3":"154","3":"157","3":"158","3":"159","3":"160"}';
my_sys_roletujing_json_array = my_sys_roletujing_json.match(/"(\d+?)":"(\d+?)"/g)
console.log(my_sys_roletujing_json_array)
for (index in my_sys_roletujing_json_array) {
console.log(my_sys_roletujing_json_array[index])
key = my_sys_roletujing_json_array[index].match(/"(\d+?)":/)
value = my_sys_roletujing_json_array[index].match(/:"(\d+?)"/)
console.log('key:'+key[1])
console.log('value:'+value[1])
}
</script>我觉得应该后台处理比较方便
import re
my_sys_roletujing_json = '{"1":"1102","1":"1103","1":"1104","1":"1105","1":"1107","1":"1108","1":"1111","1":"1112","1":"1113","1":"1114","1":"1115","1":"1116","1":"1119","1":"1120","1":"1123","1":"1125","1":"1126","1":"1127","1":"1128","1":"1129","1":"1130","1":"1131","1":"1135","1":"1136","1":"1138","1":"1139","1":"1154","1":"1155","1":"1156","1":"1159","1":"1160","1":"1161","1":"1162","1":"1163","1":"1164","1":"1165","1":"1166","1":"1172","1":"1173","1":"1175","1":"1176","1":"1177","1":"1180","3":"150","3":"151","3":"153","3":"154","3":"157","3":"158","3":"159","3":"160"}'
print(re.findall('"(\d+?)":"(\d+?)"',my_sys_roletujing_json))
#[('1', '1102'), ('1', '1103'), ('1', '1104'), ('1', '1105'), ('1', '1107'), ('1', '1108'), ('1', '1111'), ('1', '1112'), ('1', '1113'), ('1', '1114'), ('1', '1115'), ('1', '1116'), ('1', '1119'), ('1', '1120'), ('1', '1123'), ('1', '1125'), ('1', '1126'), ('1', '1127'), ('1', '1128'), ('1', '1129'), ('1', '1130'), ('1', '1131'), ('1', '1135'), ('1', '1136'), ('1', '1138'), ('1', '1139'), ('1', '1154'), ('1', '1155'), ('1', '1156'), ('1', '1159'), ('1', '1160'), ('1', '1161'), ('1', '1162'), ('1', '1163'), ('1', '1164'), ('1', '1165'), ('1', '1166'), ('1', '1172'), ('1', '1173'), ('1', '1175'), ('1', '1176'), ('1', '1177'), ('1', '1180'), ('3', '150'), ('3', '151'), ('3', '153'), ('3', '154'), ('3', '157'), ('3', '158'), ('3', '159'), ('3', '160')]
json转成list集合，然后通过linq查出相同键的数据不可以吗 比如list.where(p=>p.key==1)
– 默卿 4年前@默卿: linq?你是说用lingq.js?
– 大da脸 4年前@大da脸: 没有，我以为是后端。前端的话，你得到这个JSON的时候外层用单引号引起来变成字符串，然后去解析字符串吧，通过逗号分割成数组，再进一步通过：分割取值，存入数组。取的时候进行遍历，里面写if判断。
– 默卿 4年前@默卿: 我就是这么弄的，但是我觉得应该有什么其他的方法
– 大da脸 4年前