大佬们帮帮忙，看一下这个问题怎么解。。是一个纯粹的逻辑问题
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[待解决问题]
public class Test{
/**
* 现在程序中有一组医生排班数据，每条数据为某个医生的某天的某个时间的排班。
* 要求对这组数据进行数据转换和处理，转换成排班表格，表格通过控制台输出即可。
* 要求表头按照时间排序。如果某天没有排班，则表格不展示该列。某天某时间无数据则显示无排班。
* 上午下午晚上通过Vo中的seqNo排序。
* eg:
* 2020-05-31 2020-06-01 2020-06-02 2020-06-04
* 上午 李四 赵六 张三 无排班
* 下午 赵六 张三 赵六 张三
* 晚上 孙七 张三 无排班 张三
* 需要注意的是，最终完成代码的代码质量（逻辑是否清晰，变量/方法命名是否合理等），将作为考察标准的一部分
*/
public static void main(String[] args) {
// TODO: 打印出所有排班信息
List<TimeRangeVo> timeRangeVoList = getTimeRangeVoList();
List<SchemaVo> schemaVoList = getSchemaVoList();
}
public static List<TimeRangeVo> getTimeRangeVoList() {
List<TimeRangeVo> timeRangeVoList = new ArrayList<TimeRangeVo>();
timeRangeVoList.add(new TimeRangeVo("下午", 3));
timeRangeVoList.add(new TimeRangeVo("中午", 2));
timeRangeVoList.add(new TimeRangeVo("上午", 1));
timeRangeVoList.add(new TimeRangeVo("晚上", 4));
return timeRangeVoList;
}
public static List<SchemaVo> getSchemaVoList() {
List<SchemaVo> schemaVoList = new ArrayList<SchemaVo>();
schemaVoList.add(new SchemaVo("王五", "下午", "2020-06-04"));
schemaVoList.add(new SchemaVo("张三", "上午", "2020-06-02"));
schemaVoList.add(new SchemaVo("赵六", "下午", "2020-06-01"));
schemaVoList.add(new SchemaVo("李四", "下午", "2020-06-01"));
schemaVoList.add(new SchemaVo("王五", "下午", "2020-05-31"));
schemaVoList.add(new SchemaVo("王五", "下午", "2020-06-01"));
schemaVoList.add(new SchemaVo("李四", "下午", "2020-06-02"));
schemaVoList.add(new SchemaVo("李四", "下午", "2020-06-04"));
schemaVoList.add(new SchemaVo("孙七", "晚上", "2020-06-04"));
schemaVoList.add(new SchemaVo("张三", "下午", "2020-05-31"));
schemaVoList.add(new SchemaVo("赵六", "晚上", "2020-06-01"));
schemaVoList.add(new SchemaVo("张三", "晚上", "2020-06-04"));
schemaVoList.add(new SchemaVo("李四", "上午", "2020-05-31"));
schemaVoList.add(new SchemaVo("赵六", "上午", "2020-06-01"));
schemaVoList.add(new SchemaVo("张三", "下午", "2020-06-01"));
schemaVoList.add(new SchemaVo("赵六", "下午", "2020-05-31"));
schemaVoList.add(new SchemaVo("张三", "下午", "2020-06-02"));
schemaVoList.add(new SchemaVo("王五", "上午", "2020-05-31"));
schemaVoList.add(new SchemaVo("孙七", "晚上", "2020-05-31"));
schemaVoList.add(new SchemaVo("张三", "晚上", "2020-06-01"));
return schemaVoList;
}
static class TimeRangeVo {
String timeRangeDesc;
int seqNo;
public TimeRangeVo(String timeRangeDesc, int seqNo) {
this.timeRangeDesc = timeRangeDesc;
this.seqNo = seqNo;
}
public String getTimeRangeDesc() {
return timeRangeDesc;
}
public void setTimeRangeDesc(String timeRangeDesc) {
this.timeRangeDesc = timeRangeDesc;
}
public int getSeqNo() {
return seqNo;
}
public void setSeqNo(int seqNo) {
this.seqNo = seqNo;
}
}
static class SchemaVo {
public String doctorName;
public String timeRangeDesc;
public String schemaDate;
public SchemaVo(String doctorName, String timeRangeDesc, String schemaDate) {
this.doctorName = doctorName;
this.timeRangeDesc = timeRangeDesc;
this.schemaDate = schemaDate;
}
public String getDoctorName() {
return doctorName;
}
public void setDoctorName(String doctorName) {
this.doctorName = doctorName;
}
public String getTimeRangeDesc() {
return timeRangeDesc;
}
public void setTimeRangeDesc(String timeRangeDesc) {
this.timeRangeDesc = timeRangeDesc;
}
public String getSchemaDate() {
return schemaDate;
}
public void setSchemaDate(String schemaDate) {
this.schemaDate = schemaDate;
}
}
}
就是这个题目 按照要求打印的问题！方便的话还请贴一下代码；
所有回答(1)
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主要就是对SchemaVo对象排序吧，先通过schemaDate排序再通过timeRangeDesc排序
public static void main(String[] args) {
// TODO: 打印出所有排班信息
List<TimeRangeVo> timeRangeVoList = getTimeRangeVoList();
List<SchemaVo> schemaVoList = getSchemaVoList();
Map<String,Integer> map = new HashMap<>();
timeRangeVoList.forEach(timeRangeVo -> map.put(timeRangeVo.getTimeRangeDesc(),timeRangeVo.getSeqNo()));
timeRangeVoList.sort(Comparator.comparing(TimeRangeVo::getSeqNo));
schemaVoList.sort(Comparator.comparing(SchemaVo::getSchemaDate).thenComparing(o -> map.get(o.getTimeRangeDesc())));
Map<String,List<String>> date2SchemaVo = new LinkedHashMap<>();
Map<String,List<SchemaVo>> desc2SchemaVo = new LinkedHashMap<>();
schemaVoList.forEach(schemaVo -> {
date2SchemaVo.merge(schemaVo.getSchemaDate(), new ArrayList<String>() {{
add(schemaVo.getDoctorName());
}}, (strings, strings2) -> {
strings.addAll(strings2);
return strings;
});
desc2SchemaVo.merge(schemaVo.getTimeRangeDesc() , new ArrayList<SchemaVo>() {{
add(schemaVo);
}}, (strings, strings2) -> {
strings.addAll(strings2);
return strings;
});
});
Set<String> strings = date2SchemaVo.keySet();
List<String> objects = new ArrayList<>(strings);
System.out.println(date2SchemaVo.keySet());
desc2SchemaVo.values().forEach(schemaVos -> {
final String[] cd = {schemaVos.get(0).getSchemaDate()};
final int[] index = {0};
System.out.print(schemaVos.get(0).getTimeRangeDesc() + " ");
schemaVos.forEach(schemaVo -> {
index[0] += schemaVo.getSchemaDate().equals(cd[0]) ? 0 : 1;
cd[0] = schemaVo.getSchemaDate();
if (index[0] < objects.size() && !objects.get(index[0]).equals(schemaVo.getSchemaDate())){
System.out.print("无排期 ");
index[0]++;
}
System.out.print(schemaVo.getDoctorName() + " ");
});
while (++index[0] < objects.size()){
System.out.print("无排期");
}
System.out.println();
});
}