如何实现 TreeView 与DataGridView的联动
0
悬赏园豆：40
[已解决问题]
解决于 2010-07-25 17:24
TreeView 和DataGridView分别放在A,B 两个不同的winform当中。
点击 A当中TreeView的不同节点，B中的DataGridView数据随之改变
希望高手提供代码
最佳答案
0
Form1:
代码
Form2 fr2 = new Form2();
private void Form1_Load(object sender, EventArgs e)
{
TreeNode tt = new TreeNode("aa");
TreeNode t1 = new TreeNode("bb");
TreeNode t2 = new TreeNode("cc");
TreeNode t3 = new TreeNode("dd");
treeView1.Nodes.Add(tt);
tt.Nodes.Add(t1);
tt.Nodes.Add(t2);
tt.Nodes.Add(t3);
fr2.Show();
}
private void treeView1_AfterSelect(object sender, TreeViewEventArgs e)
{
string s = treeView1.SelectedNode.Text;
fr2.ChooseTable(s);
}
Form2:
代码
public void ChooseTable(string s)
{
DataTable dtbb = new DataTable();
DataColumn dcb1 = dtbb.Columns.Add("namebb", Type.GetType("System.String"));
DataColumn dcb2 = dtbb.Columns.Add("bid", typeof(int));
DataRow drb = dtbb.NewRow();
drb["namebb"] = "bb1";
drb["bid"] = 11;
dtbb.Rows.Add(drb);
drb = dtbb.NewRow();
drb["namebb"] = "bb2";
drb["bid"] = 22;
dtbb.Rows.Add(drb);
DataTable dtcc = new DataTable();
DataColumn dcc1 = dtcc.Columns.Add("namecc", Type.GetType("System.String"));
DataColumn dcc2 = dtcc.Columns.Add("cid", typeof(int));
DataRow drc = dtcc.NewRow();
drc["namecc"] = "cc1";
drc["cid"] = 111;
dtcc.Rows.Add(drc);
drc = dtcc.NewRow();
drc["namecc"] = "cc2";
drc["cid"] = 222;
dtcc.Rows.Add(drc);
DataTable dtdd = new DataTable();
DataColumn dcd1 = dtdd.Columns.Add("namedd", Type.GetType("System.String"));
DataColumn dcd2 = dtdd.Columns.Add("did", typeof(int));
DataRow drd = dtdd.NewRow();
drd["namedd"] = "dd1";
drd["did"] = 1111;
dtdd.Rows.Add(drd);
drd = dtdd.NewRow();
drd["namedd"] = "dd2";
drd["did"] = 2222;
dtdd.Rows.Add(drd);
DataTable dtaa = new DataTable();
DataColumn dca1 = dtaa.Columns.Add("nameaa", Type.GetType("System.String"));
DataColumn dca2 = dtaa.Columns.Add("aid", typeof(int));
DataRow dra = dtaa.NewRow();
dra["nameaa"] = "aa1";
dra["aid"] = 1;
dtaa.Rows.Add(dra);
dra = dtaa.NewRow();
dra["nameaa"] = "aa2";
dra["aid"] = 2;
dtaa.Rows.Add(dra);
DataTable dt = new DataTable();
switch (s)
{
case "aa":
this.dataGridView1.DataSource = dtaa;
break;
case "bb":
this.dataGridView1.DataSource = dtbb;
break;
case "cc":
this.dataGridView1.DataSource = dtcc;
break;
case "dd":
this.dataGridView1.DataSource = dtdd;
break;
default: break;
}
}
收获园豆：40
谢谢你的回答，你的代码没有问题，也可以正常运行，但是我的开始忘了说明，我的两个窗体到时再docking中，所有问题还是没有解决，谢谢
其他回答(1)
1
点击 A当中TreeView的不同节点向B中传递不同参数。
