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关于Form的show()方法的若干问题

0
[待解决问题]

public partial class Form2 : Form
    {
        public Form2()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {

            try
            {
                string a = textBox1.Text;

                int result;

                bool bl = int.TryParse(textBox2.Text, out  result);

                if (!bl)
                {
                    throw new YC();
                }
                else
                {
                    int b = int.Parse(textBox2.Text);
                    bool bl1 = ceshi(a, b);

                    if (bl1)
                    {
                       // MessageBox.Show("CHENGONG");
                        this.Close();
                       Form3 form3=new Form3();
                       form3.Show();

                    }
                    else
                    {
                        MessageBox.Show("SH");
                    }

                }
            }

            catch (YC yc)
            {
                MessageBox.Show(yc.ToString());
            }
            //string a = textBox1.Text;
            //int b= int.Parse(textBox2.Text);
            //bool bl = ceshi(a, b);
            //if (bl)
            //{
            //    MessageBox.Show("CHENGGONG");

            //}
            //else
            //{

            //    MessageBox.Show("SHIBAI");

            //}
            finally
            {

            }
     
        }

 

 

 

 

 

        public bool ceshi(string a, int b)
        {
            string connectionstring = "server=localhost;database=ceshi;integrated security=SSPI";
            SqlConnection con = new SqlConnection(connectionstring);
            con.Open();
            //string commandtext = "select * from Table_1 where name='" + a + "'and passward=" + b;
            //string @name;
            //string @passward;
            string commandtext = "select * from Table_1 where name=@name and passward = @passward";

            SqlCommand cmd = new SqlCommand(commandtext, con);
            //cmd.Parameters.Add("@name", SqlDbType.VarChar);
            //cmd.Parameters["@name"].Value = "a";
            cmd.Parameters.AddWithValue("@name", a);
            cmd.Parameters.Add("@passward", SqlDbType.Int);
            cmd.Parameters["@passward"].Value = b;

            SqlDataReader reader = cmd.ExecuteReader();
            if (reader.Read())
            {
                return true;
            }
            else
            {
                return false;
            }
            con.Close();

        }

     
    }

    class YC : ApplicationException
    {
        private string Message;
        public YC()
        {

            this.Message = "输入有误,请重新输入";
        }

        public override string ToString()
        {
            return Message;
        }

    }以上代码是Form2中的代码,在设置断点调试过程中弹出了Form3窗体,继续调试后会运行到Form3的方法dispose(),但是没有设置断点时没有弹出Form3,不知道什么原因, 请高手解答一下,我想弹出Form3,关闭Form2

以下是Form3中的dispose()方法:

        protected override void Dispose(bool disposing)
        {
            if (disposing && (components != null))
            {
                components.Dispose();
            }
            base.Dispose(disposing);
        }
870087629的主页 870087629 | 初学一级 | 园豆:170
提问于:2010-09-26 11:30
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所有回答(2)
0

因为你的form是主窗体..理论上它是不能被关闭的..只可以隐藏

家猫47 | 园豆:205 (菜鸟二级) | 2010-09-26 13:28
0

this.Close() 应该放在show()窗体的后面`

吖龙 | 园豆:195 (初学一级) | 2010-09-26 20:23
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