assume cs:codesg
codesg segment
mov ax,4c00h
int 21h
start:mov ax,0
s:nop
nop
mov di,offset s
mov si,offset s2
mov ax,cs:[si]
mov cs:[di],ax
s0:jmp short s
s1:mov ax,0
int 21h
mov ax,0
s2:jmp short s1
nop
codesg ends
end start
我现在对这个程序的运行过程有点不理解,希望有会汇编的牛人能给我解释一下,越详细越好!!!