各位有没有遇到多个IP且第一个可以远程的，重启电脑后程序第一次运行会出错，再次、三次运行都正常，即开机后第一次不正常，后面都正常了。

请教各位为什么开机后第一次会出错？

代码如下：

public bool MstscConnectable(string Server)

{//多个IP时循环调用此方法

try

{

axMsRdpClient4a1.Server = Server;

MstscConnecting = true;

axMsRdpClient4a1.Connect();

while (MstscConnecting)

{

Thread.Sleep(1000);

}

}

catch (Exception ex)

{

WriteLog("Server:{0} 远程桌面访问出错，错误信息：{1}", axMsRdpClient4a1.Server, ex.Message);

}

return MstscRetValue == 1;

}

private void axMsRdpClient4a1_OnConnecting(object sender, EventArgs e)

{

WriteLog("Server:{0} Connecting...", axMsRdpClient4a1.Server);

MstscRetValue = 0;

}

private void axMsRdpClient4a1_OnConnected(object sender, EventArgs e)

{

WriteLog("Server:{0} Connected.", axMsRdpClient4a1.Server);

MstscRetValue = 1;

MstscConnecting = false;

axMsRdpClient4a1.Disconnect(); //连接成功后主动断开连接

}

private void axMsRdpClient4a1_OnDisconnected(object sender, AxMSTSCLib.IMsTscAxEvents_OnDisconnectedEvent e)

{

if (MstscRetValue == 0) //MstscRetValue=0表示之前未连接成功

{

WriteLog("Server:{0} Disconnected", axMsRdpClient4a1.Server);

MstscRetValue = 2;

MstscConnecting = false;

}

}

循环调用时打印信息如下,

首次运行时：

2011-09-07 09:44:06 开始刷新远程桌面...

2011-09-07 09:44:07 Server:192.168.88.186 Connecting...

2011-09-07 09:44:18 Server:192.168.88.186 Connected.

2011-09-07 09:44:28 Server:192.168.88.186 远程桌面访问出错，错误信息：对 COM 组件的调用返回了错误 HRESULT E_FAIL。

2011-09-07 09:44:28 刷新远程桌面结束

再次、三次运行时：

2011-09-07 09:45:02 开始刷新远程桌面...

2011-09-07 09:45:02 Server:192.168.88.186 Connecting...

2011-09-07 09:45:04 Server:192.168.88.186 Connected.

2011-09-07 09:45:07 Server:192.168.88.6 Connecting...

2011-09-07 09:45:08 Server:192.168.88.6 Connected.

2011-09-07 09:45:08 刷新远程桌面结束

看首次运行时的错误信息的IP地址还是第一个，说明是在第一步axMsRdpClient4a1.Server = Server;设置IP时出错的，请教各位首次出错原因