python列表中元素间插入空行
0
悬赏园豆：10
[已解决问题]
解决于 2017-07-17 18:30
我写了一个手动输入后收集专辑信息的程序，写的很繁杂......是定义了一个可以将实参整理入字典的函数，再将字典放入列表
album_list = []
def album(name, singer, quantities_of_songs):
"""record the info of a album"""
info = {'name': a, 'singer': b, 'numbers ': c}
return info
while True:
a = input("input the name.\ninput 'q' to exit\n")
if a == 'q' :
b = c = 'q'
break
b = input("input the singer's name\n")
if b == 'q':
c = 'q'
break
c = input("input the number of songs\n")
if c == 'q':
break
recorded_album = album(a, b, c)
album_list.append(recorded_album)
question = input("do you have any other album?(yes/no)")
if question == 'no':
break
if a and b and c != 'q':
print("\n"*3)
print(album_list)
然而最后print出来的list是多个字典紧挨着排列在一起的，能否在每个元素之间插入空行使结构整洁一点
最佳答案
0
把代码排版一下，再发，Python 排版不一样结果天壤之别
print不能直接打印dict类型的数据，先转换成json格式，
print('\n'.join(album_list)) 这个可以打印换行
import json album_list = [] def album(name, singer, quantities_of_songs): """record the info of a album""" info = {'name': name, 'singer': singer, 'numbers ': quantities_of_songs} return info while True: a = input("input the name.\ninput 'q' to exit\n") if a == 'q': b = c = 'q' break b = input("input the singer's name\n") if b == 'q': c = 'q' break c = input("input the number of songs\n") if c == 'q': break recorded_album = album(a, b, c) info = json.dumps(recorded_album) album_list.append(info) question = input("do you have any other album?(yes/no)") if question == 'no': break if a and b and c != 'q': print("\n" * 3) print('\n'.join(album_list))
收获园豆：10
啊还没学过什么import json
到时候我再回来看
谢谢
