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javaweb文件上传是遇到文件名、目录名或卷标语法不正确

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[已解决问题] 解决于 2017-12-03 11:24
import java.io.File;
import java.io.IOException;
import java.util.List;

import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;

/**
 * Servlet implementation class FileUploadServlet
 */
public class FileUploadServlet extends HttpServlet
{
    private static final long serialVersionUID = 1L;

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
    {
        doPost(request, response);
    }

    
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
    {
        //解决post请求乱码
        request.setCharacterEncoding("utf-8");
        /*String name = request.getParameter("name");
        String photo = request.getParameter("photo");
        System.out.println(name+"--"+photo);
        */
        //获取一个流
        /*ServletInputStream in = request.getInputStream();
        String str = IOUtils.toString(in);
        System.out.println(str);*/
        //获取一个工厂类实例
        DiskFileItemFactory factory=new DiskFileItemFactory();
        //创建解析器实例
        ServletFileUpload fileUpload=new ServletFileUpload(factory);
        try
        {
            //解析request
            List<FileItem> fileItems = fileUpload.parseRequest(request);
            //System.out.println(fileItems.size());
            //遍历fileItems,读取表单的信息
            for (FileItem fileItem : fileItems)
            {
                //判断当前表单项是否是一个普通表单项
                if(fileItem.isFormField())
                {
                    //获取属性名
                    String fieldName = fileItem.getFieldName();
                    //获取属性值
                    String value = fileItem.getString("utf-8");
                    System.out.println(fieldName+"="+value);
                }else 
                {
                    //如果是文件表单项
                    //获取文件的大小
                    long size = fileItem.getSize();
                    //获取文件的类型
                    String contentType = fileItem.getContentType();
                    //获取文件的名字
                    String name = fileItem.getName();
                    
                    //获取表单项的属性名
                    String fieldName = fileItem.getFieldName();
                    System.out.println("文件的大小:"+size);
                    System.out.println("文件的类型:"+contentType);
                    System.out.println("文件的名字:"+name);
                    System.out.println("表单项name属性名:"+fieldName);
                    //获取ServletContext对象
                    ServletContext context = this.getServletContext();
                    //获取项目的真实路径
                    String path = context.getRealPath("/upload");
                    //判断路径是否存在
                    File file=new File(path);
                    if(!file.exists())
                    {
                        //如果不存在该路径,则创建一个路径
                        file.mkdirs();
                    }
                    
                    System.out.println(path);
                    //将文件写入到磁盘中
                    fileItem.write(new File(path+"/"+name));
                    
                }
                
            }
            
        } catch (FileUploadException e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (Exception e)
        {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } 
        
    }

}
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最佳答案
0

建议打印出完整的path+"/"+name文件路径看是否有问题

奖励园豆:5
dudu | 高人七级 |园豆:30880 | 2017-11-27 17:12

对不起刚才没发错误信息

name=xx
java.io.FileNotFoundException: D:\java ee\.metadata\.plugins\org.eclipse.wst.server.core\tmp0\wtpwebapps\WEB_FileUpload1\upload\C:\愤怒.png (文件名、目录名或卷标语法不正确。)
文件的大小:136008
文件的类型:image/png
文件的名字:C:\愤怒.png
表单项name属性名:photo
D:\java ee\.metadata\.plugins\org.eclipse.wst.server.core\tmp0\wtpwebapps\WEB_FileUpload1\upload
    at java.io.FileOutputStream.open0(Native Method)
    at java.io.FileOutputStream.open(FileOutputStream.java:270)
    at java.io.FileOutputStream.<init>(FileOutputStream.java:213)
    at java.io.FileOutputStream.<init>(FileOutputStream.java:162)
    at org.apache.commons.fileupload.disk.DiskFileItem.write(DiskFileItem.java:417)
    at com.atguigu.FileUpload1.FileUploadServlet.doPost(FileUploadServlet.java:93)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:650)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:731)
妈妈说名字要高调 | 园豆:-20 (初学一级) | 2017-11-27 17:14

大哥,D:\java ee\.metadata\.plugins\org.eclipse.wst.server.core\tmp0\wtpwebapps\WEB_FileUpload1\upload\C:\愤怒.png (文件名、目录名或卷标语法不正确。)是这里的问题吗?

 

妈妈说名字要高调 | 园豆:-20 (初学一级) | 2017-11-27 17:15

@妈妈说名字要高调: 路径中多了C:\,需要去掉

dudu | 园豆:30880 (高人七级) | 2017-11-27 17:19

@dudu: 好了,谢谢大哥。

经过测试在获取文件名那行代码下加入如下代码就能完美解决问题,希望遇到这个问题的同学别再走弯路。

if(name.contains("\\"))
                    {
                        //如果包含则截取字符串
                        name=name.substring(name.lastIndexOf("\\")+1);
                    }
妈妈说名字要高调 | 园豆:-20 (初学一级) | 2017-11-27 17:28
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