php 两个数组，若键相同，则值合并
0
[待解决问题]
将下列两个数组:
$arr1 = array('9' => '4.08', '10' => '0.10', '11' => '4.08', '12' => '0.01');
$arr2 = array('8' => '0.01', '10' => '0.01', '11' => '0.01');
合并成如下格式:
$arr3 = array('8' => '0.01', '9' => '4.08', '10' => '0.11', '11' => '4.09', '12' => '0.01');
即，键相同则值相加，并原样保留无相同键值对。
所有回答(2)
0
看下能用吗：
<!DOCTYPE html>
<html>
<body>
<?php
$arr1 = array('9' => '4.08', '10' => '0.10', '11' => '4.08', '12' => '0.01');
$arr2 = array('8' => '0.01', '10' => '0.01', '11' => '0.01');
$arr3 = $arr1;//把数组1赋值给新的数组3
foreach($arr2 as $x=>$x_value)//遍历数组2
{
if (array_key_exists($x, $arr3)) {//如果存在key，则值相加
$arr3[$x] += $arr2[$x];
}
else {//不存在key，则新增
$arr3[$x] = $x_value;
}
}
ksort($arr3);//根据key进行升序排列
foreach($arr3 as $x=>$x_value)
{
echo "Key=" . $x . ", Value=" . $x_value;
echo "<br>";
}
?>
</body>
</html>
0
$arr1 = array('9' => '4.08', '10' => '0.10', '11' => '4.08', '12' => '0.01');
$arr2 = array('8' => '0.01', '10' => '0.01', '11' => '0.01');
$arr = [];
foreach ($arr1 as $key => $value) {
if(isset($arr[$key])){
$arr[$key] += $value;
}else{
$arr[$key] = $value;
}
}
foreach ($arr2 as $key => $value) {
if(isset($arr[$key])){
$arr[$key] += $value;
}else{
$arr[$key] = $value;
}
}
ksort($arr);