关于WebService的问题
0
悬赏园豆：50
[已解决问题]
解决于 2021-03-17 09:48
先有一个WebService地址，目前我可以通过SoapUI测试成功并返回数据，但是用POSTMAN和Java的代码拼接同样的请求信息则只能返回WSDL文档内容，不返回数据，请问各位大佬这是什么原因导致的？万分感谢
最佳答案
0
贴出你的代码看看吧。理论上不应该出现这样的情况
下面是soap请求，
POST /service.soap HTTP/1.1 Host: 192.168.1.2 Content-Type: text/xml; charset=utf-8 Content-Length: 152 SOAPAction: "" <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> ******************* </soap:Body> </soap:Envelope>
下面是普通http请求
POST /q HTTP/1.1 Content-Type: application/x-www-form-urlencoded; charset=utf-8 Host: 192.168.1.2 Connection: close User-Agent: Mozila 5.0 Content-Length: 62 k=FOgc3OgR9s2Rl4XfCFL6BNrXqgDCzbP9qkSMweKU5ohkqCg=&v=H7O58qBc7A+8QJE7rqG8duDb7aKo==
你可以发现，除了数据格式不同，其他基本都是一样的。如果返回数据不对，肯定是你写的有问题，抓包看一下吧
收获园豆：50
public class xxx{
public static void doPostOrGet(String path,String data) {
PrintWriter out = null;
String result = "";
BufferedReader br = null;
try {
URL url = new URL(path);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
String xmlInfo = getXmlInfo();
byte[] xmlData = xmlInfo.getBytes();
conn.setRequestMethod("POST");
conn.setUseCaches(false);
conn.setRequestProperty("accept", "*/*");
conn.setRequestProperty("Charset", "utf-8");
conn.setRequestProperty("connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "text/xml");
conn.setRequestProperty("Content-length",String.valueOf(xmlData.length));
conn.setRequestProperty("Accept-Encoding", "gzip,deflate");
conn.setRequestProperty("user-agent", "Apache-HttpClient/4.1.1");
conn.setRequestProperty("SOAPAction","XXX");
conn.setDoOutput(true);
conn.setDoInput(true);
String encodings = Base64.getEncoder().encodeToString(("XXX:PPP").getBytes("utf-8"));
conn.setRequestProperty("Authorization", "Basic " + encodings);
conn.connect();
//out = new PrintWriter(conn.getOutputStream());
OutputStreamWriter outer = new OutputStreamWriter(conn.getOutputStream(),"UTF-8");
//out.print(xmlData);
//out.flush();
outer.write(xmlInfo);
outer.flush();
outer.close();
int a = conn.getResponseCode();
String c = conn.getResponseMessage();
BufferedReader br1 = new BufferedReader(new InputStreamReader(conn.getInputStream(),"UTF-8"));
StringBuffer xml = new StringBuffer();
String str = "";
while ((str = br1.readLine()) != null) {
xml.append(str);
System.out.println(str);
}
br1.close();
conn.disconnect();
}catch(Exception e) {
e.printStackTrace();
}finally {
try {
if (out != null){
out.close();
}
// if (outer != null){
// outer.close();
// }
if (br != null){
br.close();
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
public static void main(String arg[]) {
doPostOrGet("XXX","");
}
//拼接请求报文XML
private static String getXmlInfo() {
StringBuffer sb = new StringBuffer();
sb.append(" <soapenv:Envelope xmlns:soap=\"http://www.w3.org/2003/05/soap-envelope\" xmlns:urn=\"XXX\" soap:encodingStyle=\"http://www.w3.org/2001/12/soap-encoding\"> ");
sb.append(" <soapenv:Header/>");
sb.append(" <soapenv:Body>");
sb.append(" <urn:XXX>");
sb.append(" </urn:XXX>");
sb.append(" </soapenv:Body>");
sb.append(" </soapenv:Envelope>");
return sb.toString();
}
}
@你的胖子: 抓包看下就清楚了。看下两个客户端发出的数据有什么不同。再做针对性修改就行
@龙葛格: 按照抓包工具的请求头修改了 但是还是没效果
@龙葛格: 谢了 后来找到了FullPath，操作了一下调试通了~
其他回答(1)
0
简单点，找个webservice的java框架调用好了，比如CXF
CXF也试了，没效果
