这是源码

import requests
from bs4 import BeautifulSoup
import time

url = "https://movie.douban.com/top250?start=0&filter="

headers = {
"User-Agent": """Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/122.0.0.0 Safari/537.36"""
}

urls = ["https://movie.douban.com/top250?start=%d&filter=" % i
for i in range(0, 226, 25)
]

for url in urls:
resp = requests.get(url, headers=headers)
soup = BeautifulSoup(resp.text, "html.parser")
print(resp.status_code)
print("当前网页:", url, resp.status_code)
for li in soup.find_all("li"):
items = li.find("div", class_="item")
if not items:
continue

    Tops = items.find("div", class_="pic").find("em").get_text()  # 排名

    imgs = li.find("img")
    src = imgs["src"]  # 图片地址

    Titles = items.find("div", class_="hd").find("span").get_text()  # 电影名

    Directors = items.find("div", class_="bd").find("p").get_text().strip().replace("\n", "<br/>").replace('',
                                                                                                           ' ').replace(
        "<br/>                            ", "\t")  # 导演

    Score = items.find("div", class_="star").find("span", class_="rating_num").get_text()  # 评分

    spans = items.find("div", class_="star").find_all("span")

    inq = items.find("p", class_="quote")  # 简介
    if not items.find("p", class_="quote"):
        continue

    print(Tops, Titles, src, Directors, Score, spans[3].text, inq.find("span").get_text())

time.sleep(5)  # 防止爬取太快ip被封  根据网页的robots.txt文件![](https://img2024.cnblogs.com/q/2339399/202404/2339399-20240409172631342-939615220.png)

在我刚写好的时候没有问题，就在我想封装成一些函数运行之后出现了这个错误，我把函数注释以后这个问题还时有，但是在我复制这些代码在桌面运行的时候却可以爬取到。请问我该怎么解决