HttpWebRequest的post方式！帮帮我吧！大哥大姐们！
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悬赏园豆：100
[已关闭问题]
关闭于 2012-05-31 09:54
private void SendPost() { var url = http://ip:port/test.jsp; // Create the web request object HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url); webRequest.Method = "POST"; webRequest.ContentType = "application/x-www-form-urlencoded"; // Start the request webRequest.BeginGetRequestStream(new AsyncCallback(GetRequestStreamCallback), webRequest); } private void GetRequestStreamCallback(IAsyncResult asynchronousResult) { HttpWebRequest webRequest = (HttpWebRequest)asynchronousResult.AsyncState; // End the stream request operation Stream postStream = webRequest.EndGetRequestStream(asynchronousResult); // Create the post data // Demo POST data string postData = "SubmitIMLogin=1&phone=11111111"; byte[] byteArray = Encoding.UTF8.GetBytes(postData); // Add the post data to the web request postStream.Write(byteArray, 0, byteArray.Length); postStream.Close(); // Start the web request webRequest.BeginGetResponse(new AsyncCallback(GetResponseCallback), webRequest); } private void GetResponseCallback(IAsyncResult asynchronousResult) { try { HttpWebRequest webRequest = (HttpWebRequest)asynchronousResult.AsyncState; HttpWebResponse response; // End the get response operation response = (HttpWebResponse)webRequest.EndGetResponse(asynchronousResult); Stream streamResponse = response.GetResponseStream(); StreamReader streamReader = new StreamReader(streamResponse); var Response = streamReader.ReadToEnd(); streamResponse.Close(); streamReader.Close(); response.Close(); Dispatcher.BeginInvoke(() => //传给主线程结果 { MessageBox.Show(Response); }); } catch (WebException e) { Dispatcher.BeginInvoke(() => //传给主线程结果 { MessageBox.Show(e.ToString()); }); } }
帮我解决这个异常。
或者你能否给我一个简单的例子，一个地址一个参数。用Http Post 的方式获取数据呢
Url：http://ip:port/11111.asp
postData：SubmitIMLogin=1&phone=111111
所有回答(4)
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你是想Post data，还是想从模仿Web Server那样？
如果是Post data
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
webRequest.Method = "POST";
webRequest.ContentType = "application/x-www-form-urlencoded";
var stream=webRequest.GetRequestStream(); //往Stream 写 postData。
@哲凯: 手上暂时没有IDE，将就一下
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
webRequest.Method = "POST";
webRequest.ContentType = "application/x-www-form-urlencoded";
var stream=webRequest.GetRequestStream();
using(var writer=new StreamWriter(stream))
{
writer.Write(postData);
writer.Flush();
}
responseStream = webRequest.GetResponse().GetResponseStream();
using(var reader=new StreamReader(reponseStream))
{
// do sometihing.
}
@沉默的糕点: 返回值在什么地方获取？
@哲凯:
ResponseStream 就是你要的返回值，按照字符方式处理就可以了，也就是说，你返回的是Json，那么就按Json处理，如果是Html，那么久里面就是Html。
@沉默的糕点: 恕在下，不知。
我先试试，总之还是谢谢你的帮助！
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我要的是在widowc Phone里面进行Post不是asp.net啊。Phone里面好多东西都没有！
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牛，搞WP的！应该思路差不多，只是WP把很多东西都省略了，毕竟运行环境不同。
不过呢，你可以把.NET里的实现过程反射出来分析，然后想办法在WP中自己写一个类库来实现，就用Waters提供的连接http://www.cnblogs.com/ThomasNet/archive/2007/09/03/879331.html，我一般都是用这样的方法解决，呵呵，有点暴力有点黄。
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同求解 我也是这样写 但是到了Stream postStream = webRequest.EndGetRequestStream(asynchronousResult);
就报错 各种不懂啊
