调试时有错而运行正常
0
悬赏园豆：50
[已解决问题]
解决于 2017-04-10 14:30
以下这段代码我在Visual Studio中运行时会报错（线程间操作无效: 从不是创建控件“Form1”的线程访问它。）
为什么直接运行exe没有问题？
private void button1_Click(object sender, EventArgs e)
{
MessageBox.Show("kaishi");
BackgroundWorker BackGW = new BackgroundWorker();
BackGW.DoWork += bwload_DoWork;
BackGW.RunWorkerAsync();
}
private void bwload_DoWork(object sender, DoWorkEventArgs e)
{
Form2 jd = new Form2();
FormCollection forms = Application.OpenForms;
Form formTemp = forms[0];
IWin32Window owner = formTemp;
jd.ShowDialog(owner);
MessageBox.Show("jieshu");
}
{
MessageBox.Show("kaishi");
BackgroundWorker BackGW = new BackgroundWorker();
BackGW.DoWork += bwload_DoWork;
BackGW.RunWorkerAsync();
}
private void bwload_DoWork(object sender, DoWorkEventArgs e)
{
Form2 jd = new Form2();
FormCollection forms = Application.OpenForms;
Form formTemp = forms[0];
IWin32Window owner = formTemp;
jd.ShowDialog(owner);
MessageBox.Show("jieshu");
}
private void button1_Click(object sender, EventArgs e) { MessageBox.Show("kaishi"); BackgroundWorker BackGW = new BackgroundWorker(); BackGW.DoWork += bwload_DoWork; BackGW.RunWorkerAsync(); } private void bwload_DoWork(object sender, DoWorkEventArgs e) { Form2 jd = new Form2(); FormCollection forms = Application.OpenForms; Form formTemp = forms[0]; IWin32Window owner = formTemp; jd.ShowDialog(owner); MessageBox.Show("jieshu"); }
最佳答案
0
其他回答(2)
1
所有STA线程的数据还是乖乖用Dispatcher访问比较好
0
http://www.cnblogs.com/tom-tong/archive/2012/02/22/2363965.html
BackgroundWorker 不能这样用.
收获园豆：10
