<string>{"img":[{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"},{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"},{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"},{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"}]}</string>

那这样的格式呢？  问题的格式是我自己写的。这些事生成的，但是在前台也没法处理

@Like金: 这个是可以的

@Like金: JSON.parse(str.substring(str.indexOf("{"),str.lastIndexOf("}")+1))

 测试通过

@codingHeart: TypeError: str.replace is not a function   提示不是一个函数，是不是得引用什么啊？

如图：

@Like金: 给定的json字符串加上单引号‘’        var str = ‘<string>{"img":[{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"},{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"},{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"},{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"}]}</string>’

@Like金: 你发的新json字符串格式不需要replace函数了

var str = ‘<string>{"img":[{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"},{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"},{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"},{"ID":"0","FileUpName":"A00003.jpg","UpdateFileUpName":"","UpLoadPath":"","SavePath":"C:\Users\yangjinlei\Desktop\image\A00003.jpg","SaveTime":"","UserId":"0"}]}</string>’

var result = JSON.parse(str.substring(str.indexOf("{"),str.lastIndexOf("}")+1))

我这边能通过  处理方式应该没问题的

@codingHeart: 

$.ajax({
type: "get",
//contentType: "application/json;charset=utf-8", //WebService 会返回Json类型
url: "http://localhost:54753/WebService1.asmx/FileShowListString", //调用WebService
//dataType: 'string',
headers: { "Access-Control-Allow-Origin": "*" },
data: { id: 1 },
success: function (result) {
var str = result;
//JSON.parse(str.substring(str.indexOf("{"), result.lastIndexOf("}") + 1));
alert(JSON.parse(str.substring(str.IndexOf("{"), str.lastIndexOf("}") + 1)));
},
error: function (err, status) {

alert("请求失败！");
}
});

@codingHeart: 

@codingHeart: 

@codingHeart: 还是不行啊

@Like金:  看着没问题啊  var str = “‘”+ result+“’”;这个地方试一下吧

@Like金: 小写的indexOf()啊

@Like金: json那段函数直接copy我的吧.....

@codingHeart: 就是copy你的啊但是还是不行。TypeError: str.indexOf is not a function

这个错误。

@Like金: 吃饭去了

var str = “‘”+ result+“’”；这条语句换了没的，indexOf是String的函数，不会没有的

@Like金: 

把这个代码跑一下，给我看下结果，WebService可以返回json格式的数据的，你那个返回的是xml

$.ajax({
type: "POST",
//contentType: "application/json;charset=utf-8", //WebService 会返回Json类型
url: "http://localhost:54753/WebService1.asmx/FileShowListString", //调用WebService
dataType: 'json',
//headers: { "Access-Control-Allow-Origin": "*" },
data: { id: 1 },
success: function (result) {
//var str = “‘”+ result+“’”;
//JSON.parse(str.substring(str.indexOf("{"), result.lastIndexOf("}") + 1));
//alert(JSON.parse(str.substring(str.IndexOf("{"), str.lastIndexOf("}") + 1)));
console.log(result);
},
error: function (err, status) {

alert("请求失败！");
}
});

@codingHeart: 这样就提示请求失败了，

public string FileShowListString(int id)
        {
            Context.Response.AddHeader("Access-Control-Allow-Origin", "*");
            List<object> list = new List<object>();
            StringBuilder str = new StringBuilder();
            str.Append("select * from FileUptab where UserId=" + id);
            DataTable dt = DBhelper.GetTable(str.ToString());
            FileUpLoad img = new FileUpLoad();
            foreach (DataRow dr in dt.Rows)
            {
                img.FileUpName = dr["FileUpName"].ToString();
                img.SavePath = dr["SavePath"].ToString();
                list.Add(img);
            }
            ObjectListToJSONcs t = new ObjectListToJSONcs();
            string json = t.toJSON(list,"img");
            return json.ToString();
        }

这是我web service

@Like金:  最后一句（return json.ToString();）换成Context.Response.Write(json.ToString());应该就可以了

@codingHeart:   反不回去

@Like金: 后台代码不能改？

@codingHeart: 

@Like金: 函数定义的string 换成void，你这得上点心啊，兄弟

@codingHeart: 

不是我不上心啊  这没法返回啊

@Like金: 不要return.................

@codingHeart: .... 还是不行 不要return 就没有数据了，还报数据库连接错误。

@Like金: 

public void FileShowListString(int id)
        {
            Context.Response.AddHeader("Access-Control-Allow-Origin", "*");
            List<object> list = new List<object>();
            StringBuilder str = new StringBuilder();
            str.Append("select * from FileUptab where UserId=" + id);
            DataTable dt = DBhelper.GetTable(str.ToString());
            FileUpLoad img = new FileUpLoad();
            foreach (DataRow dr in dt.Rows)
            {
                img.FileUpName = dr["FileUpName"].ToString();
                img.SavePath = dr["SavePath"].ToString();
                list.Add(img);
            }
            ObjectListToJSONcs t = new ObjectListToJSONcs();
            string json = t.toJSON(list,"img"); 
            Context.Response.Write(json.ToString());
            Context.Response.End();
        }

这应该不干数据库的事儿啊

@codingHeart: 好啦。可以了，刚才数据库服务自动给关了，尴尬。。。。。我才发现。

谢谢你啦，奖励给你翻倍。么么哒。

@Like金: 

感动死我了，也不好意思，能改后台的话，第一时间应该让你改后台的，折腾这么久。

@codingHeart: 哈哈，还是谢谢你，帮我折腾这么长时间。