请问怎么实现两个checkbox都做全选按钮
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[待解决问题]
请问怎么实现两个checkbox都做全选按钮：
<input id="check" onclick="checkAll()" type="checkbox" name="checkbox1" value="checkbox"/>
<input id="check" onclick="checkAll()" type="checkbox" name="checkbox2" value="checkbox"/>
<script>
function checkAll() {
var checked = document.getElementById("check").checked;
var checkson = document.getElementsByName("checkbox2");
if(checked) {
for(var i = 0; i < checkson.length ;i++) {
checkson[i].checked = true;}}
else {
for(var i = 0; i < checkson.length ;i++) {
checkson[i].checked = false;}}
}
</script>
所有回答(3)
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你想干嘛啊，没看明白。另外你的id也重复了
想这样实现，两个都可以全选
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<input id="check1" onclick="javascript:$('#check2').click()" type="checkbox" name="checkbox1" value="checkbox"/>
<input id="check2" onclick="checkAll()" type="checkbox" name="checkbox2" value="checkbox"/>多谢哦。还有位老哥这样写，分享一下：
<input id="check1" onclick="checkAll(this.checked)" type="checkbox" name="checkbox1" value="checkbox"/>
<input id="check2" onclick="checkAll(this.checked)" type="checkbox" name="checkbox1" value="checkbox"/>
<hr>
<input type="checkbox" name="checkbox2" value="checkbox"/>
<input type="checkbox" name="checkbox2" value="checkbox"/>
<input type="checkbox" name="checkbox2" value="checkbox"/>
<script>
function checkAll(checked) {
document.getElementById("check1").checked = checked;
document.getElementById("check2").checked = checked;
var checkson = document.getElementsByName("checkbox2");
if(checked) {
for(var i = 0; i < checkson.length ;i++) {
checkson[i].checked = true;}}
else {
for(var i = 0; i < checkson.length ;i++) {
checkson[i].checked = false;}}
}
</script>
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