如何能让这个滑屏页每到一个页面动画能重新播放一次，，我这个动画播了一次就停止了，后面就无法进行了
0
悬赏园豆：5
[已解决问题]
解决于 2016-05-21 17:04
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <meta http-equiv="Content-Type" content="text/html;charset=UTF-8"> <meta content="width=device-width, initial-scale=1.0, minimum-scale=1.0, maximum-scale=1.0,user-scalable=no" name="viewport" id="viewport" /> <title>上下滑动</title> <link rel="stylesheet" type="text/css" href="css/style.css" /> <script type="text/javascript" src="http://libs.useso.com/js/jquery/1.7.2/jquery.min.js"></script> <script type="text/javascript" src="js/jquery.touchSwipe.min.js"></script> <style> .rspimg1{ width: 100%; } </style> <script type="text/javascript"> $(document).ready( function() { var nowpage = 0; //给最大的盒子增加事件监听 $(".container").swipe( { swipe:function(event, direction, distance, duration, fingerCount) { if(direction == "up"){ nowpage = nowpage + 1; }else if(direction == "down"){ nowpage = nowpage - 1; } if(nowpage > 2){ nowpage = 2; } if(nowpage < 0){ nowpage = 0; } $(".container").animate({"top":nowpage * -100 + "%"},400); $(".page").eq(nowpage).addClass("cur").siblings().removeClass("cur"); } } ); } ); </script> </head> <body onmousewheel="return false;"> <!--效果html开始--> <div class="container"> <div class="page page0 cur"> <div class="fade_animation2" ><img class='rspimg1' src="images/10.1.png" ondrag="return false"></div> <div class="fade_animation2" ><img class='rspimg1' src="images/10.2.png" ondrag="return false"></div> <div class="fade_inUp" ><img class='rspimg1' src="images/10.3.png" ondrag="return false"></div> <div class="fade_inUp" ><img class='rspimg1' src="images/10.4.png" ondrag="return false"></div> </div> <div class="page page1"> <div class="fade_animation2" ><img class='rspimg1' src="images/11.1.png" ondrag="return false"></div> <div class="fade_animation2" ><img class='rspimg1' src="images/11.2.png" ondrag="return false"></div> </div> <div class="page page2"> <div class="fade_animation2" ><img class='rspimg1' src="images/12.1.png" ondrag="return false"></div> <div class="fade_animation2" ><img class='rspimg1' src="images/12.2.png" ondrag="return false"></div> <div class="fade_inUp" ><img class='rspimg1' src="images/12.3.png" ondrag="return false"></div> <div class="fade_inUp" ><img class='rspimg1' src="images/12.4.png" ondrag="return false"></div> </div> </div> <!--效果html结束--> <script type="text/javascript"> /* $(document).ready(function(){ alert($(window).height()); //浏览器当前窗口可视区域高度 })*/ function browserRedirect() { var sUserAgent = navigator.userAgent.toLowerCase(); var bIsIpad = sUserAgent.match(/ipad/i) == "ipad"; var bIsIphoneOs = sUserAgent.match(/iphone os/i) == "iphone os"; var bIsMidp = sUserAgent.match(/midp/i) == "midp"; var bIsUc7 = sUserAgent.match(/rv:1.2.3.4/i) == "rv:1.2.3.4"; var bIsUc = sUserAgent.match(/ucweb/i) == "ucweb"; var bIsAndroid = sUserAgent.match(/android/i) == "android"; var bIsCE = sUserAgent.match(/windows ce/i) == "windows ce"; var bIsWM = sUserAgent.match(/windows mobile/i) == "windows mobile"; var height=window.screen.Height; if (bIsIpad || bIsIphoneOs || bIsMidp || bIsUc7 || bIsUc || bIsAndroid || bIsCE || bIsWM) { //alert("phone"); } else if ($(window).height()==590) { $('.container .page').css("width","355px").css("margin","0 auto"); $('.p-ct').css("margin","0 auto"); $(".pic1").css("width","50%"); $(".back").css("width","11%"); }else{ //alert("pc"); $('.container .page').css("width","410px").css("margin","0 auto"); $('.p-ct').css("margin","0 auto"); $(".pic1").css("width","50%"); $(".back").css("width","11%"); } } browserRedirect(); </script> </body> </html>
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最佳答案
0
你可以根据你container的top值，判断来写事件，当值不同的时候 在处罚你的动画效果 就可以了
收获园豆：5
var temp=$(".container").css("top"); alert(temp); if (temp==0) { alert(222); $(".rspimg1").addClass("fade_animation2"); };
这是写错了吗，没有效果
@像风一样自由~~~: var temp=parseInt($(".container").css("top"))；你alert出来的是什么，条件写的是什么，明显代码错了
@Cuntain√:
var temp=parseInt($(".container").css("top")) console.log(temp); //alert(temp); if (temp==-568) { $(".a").addClass("fade_animation2"); $(".b").addClass("fade_inUp"); }; if (temp==0) { $(".a").addClass("fade_animation2"); $(".b").addClass("fade_inUp"); };
这个样子？
@Cuntain√: 行不通
@像风一样自由~~~: 哪里不通？alert有效果吗
@Cuntain√:
if (temp==0) { alert(1); $(".a").addClass("fade_animation2"); $(".b").addClass("fade_inUp"); }; if (temp==-($(window).height())) { alert(2); $(".c").addClass("fade_animation"); $(".d").addClass("fade_animation2"); };
这样写可以，，但是返回滑动的时候动画又没有任何效果了，这是为什么
@像风一样自由~~~: 你第一次滑动过去的时候，你添加class了，第二次的时候class还在 所以没有动画，
if (temp==0) { alert(1);
$(".a").addClass("fade_animation2");
$(".b").addClass("fade_inUp"); };
$(".c").removeClass("fade_animation");
$(".d").removeClass("fade_animation2"); };
if (temp==-($(window).height())) { alert(2);
$(".a").removeClass("fade_animation2");
$(".b").removeClass("fade_inUp"); };
$(".c").addClass("fade_animation");
$(".d").addClass("fade_animation2"); };
我这个是就你的问题回答的，当满足条件的时候，addClass，不满足这个条件的时候，记得删除，就可以了
@像风一样自由~~~: 就是每次滑动到那得时候， 添加一次，划过去了 删除，再划过来的时候 再添加，大概就是这个样子，这和tab切换 基本一个道理
@Cuntain√: 
@Cuntain√: 多了俩括号，而且去掉后也没有效果
括号多了，你去掉，就是每次滑动到那的时候， 添加一次，划过去了 删除，再划过来的时候 再添加，大概就是这个样子，这和tab切换 基本一个道理 ，你再好好想想
@Cuntain√: 你知不知道如何控制它的滑动次数呀，就是滑到第三次，temp不能累加？？
@像风一样自由~~~:这个 写if（temp>=a)的时候 temp=a 就好
